3[-3(2x+4)+3(3x-3)]=

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Solution for 3[-3(2x+4)+3(3x-3)]= equation: 


Simplifying
3[-3(2x + 4) + 3(3x + -3)] = 0

Reorder the terms:
3[-3(4 + 2x) + 3(3x + -3)] = 0
3[(4 * -3 + 2x * -3) + 3(3x + -3)] = 0
3[(-12 + -6x) + 3(3x + -3)] = 0

Reorder the terms:
3[-12 + -6x + 3(-3 + 3x)] = 0
3[-12 + -6x + (-3 * 3 + 3x * 3)] = 0
3[-12 + -6x + (-9 + 9x)] = 0

Reorder the terms:
3[-12 + -9 + -6x + 9x] = 0

Combine like terms: -12 + -9 = -21
3[-21 + -6x + 9x] = 0

Combine like terms: -6x + 9x = 3x
3[-21 + 3x] = 0
[-21 * 3 + 3x * 3] = 0
[-63 + 9x] = 0

Solving
-63 + 9x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '63' to each side of the equation.
-63 + 63 + 9x = 0 + 63

Combine like terms: -63 + 63 = 0
0 + 9x = 0 + 63
9x = 0 + 63

Combine like terms: 0 + 63 = 63
9x = 63

Divide each side by '9'.
x = 7

Simplifying
x = 7

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